ANSWER:
$814.49
Explanation:
Given:
Principal (P) = $3000
Rate (r) = 1.5%
Tim (t) = 4
For continuously compounded formula is the following:
![\begin{gathered} A=P\cdot e^(rt) \\ \\ \text{ We replacing:} \\ \\ A=3000\cdot e^(0.015\cdot4) \\ \\ A=3185.51 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/yhg8yxri8dd7f3cfa9bfnamrhv69bs061z.png)
This means after 4 years Trafton has $3185.51 in his savings account, what he needs to get up to $4000 is calculated by the following subtraction:
![\begin{gathered} a=4000-3185.51 \\ \\ a=841.49 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gep8rzpyvpwlrj504c0nhc3iyiaznh7xz3.png)
This means that he needs an additional $814.49 to buy the car.