27.1k views
1 vote
In a circus, an average of 500 people pay $15 each to attend a performance. For each $2 increase in ticket price, the number of ticket buyers will decrease by 40. Find the number of dollars the price must be increased to achieve maximum revenue.

1 Answer

4 votes

Problem

In a circus, an average of 500 people pay $15 each to attend a performance. For each $2 increase in ticket price, the number of ticket buyers will decrease by 40. Find the number of dollars the price must be increased to achieve maximum revenue.​

Solution

For this case we need to find a function for the attendance and other for the ticket price. and then multiply the two functions:

Price: 15 + 2x

Attendance: 500 -40x

x represent the number of $2 increases

And the revenue would be given by:

R = P* A

R = (15+2x)(500-40x)

R= 7500 - 600x +1000 x -80x^2

R= -80x^2 +400x +7 500

And if we take the derivate of this function we got:

R' = -160 x +400= 0

And solving for x we got:

x= 400/160= 2.5$ would be the increase

And the price would be:

P= 15 +2.5 *2= 20$ per ticket

User Irvin
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories