From the given, let n = 50, x = 4, p = 0.113, and q = 1-0.113 = 0.887.
Since we need to find the probability that exactly 4 of the respondents are on debt, we need to look for P(4). Thus, we need to look for P(4 female undergraduates take on debt).
To obtain this, substitute the given values into the binomial probability formula.
![P(x)=_nC_xp^xq^(n-x)](https://img.qammunity.org/2023/formulas/mathematics/college/8vefjdw1o15pfvp0r8e083b1yz8yhzod8m.png)
Thus, we have the following.
![\begin{gathered} \\ P(4)=_(50)C_4(0.113)^4(0.887)^(50-4) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/cf6swl7yasrl3kd37kjcxqeiu6ubrf8r49.png)
Simplify the combination and the exponenial expressions.
![\begin{gathered} P(4)=(230300)(0.113)^4(0.887)^(50-4) \\ =(230300)(0.113)^4(0.887)^(46) \\ \approx(230300)(0.000163047361)(0.004022411635) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/cie6j4pugtyn6hrlr54wm9y7o1xpkiz0pg.png)
Simplify the expression. Multiply.
![\begin{gathered} P(4)\approx0.1510407815 \\ \approx0.151 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/bbfnxlh82m55up572grk7g9csfdik0jrnv.png)
Therefore, the probability that exactly 4 female undergradraduates take on debt is about 0.151.