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First, we find the area of the square knowing that its side length is 22 feet.


A_{\text{square}}=(22ft)^2=484ft^2

The area of an equilateral triangle is


A_{\text{equilateral}}=\frac{\sqrt[]{3}}{4}a^2

Where a = 22 ft.


A_{\text{equilateral}}=\frac{\sqrt[]{3}}{4}\cdot(22ft)^2=\frac{484\sqrt[]{3}}{4}ft^2=121\sqrt[]{3}ft^2

Then, we find the area of the right triangle


A_{\text{right}}=(bh)/(2)=(16ft\cdot22ft)/(2)=176ft^2

At last, we add all three areas


A=484ft^2+121\sqrt[]{3}ft^2+176ft^2\approx869.6ft^2

Hence, the area of the composite figure is 869.6 square feet.

User Finglas
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