First, we find the area of the square knowing that its side length is 22 feet.

The area of an equilateral triangle is
![A_{\text{equilateral}}=\frac{\sqrt[]{3}}{4}a^2](https://img.qammunity.org/2023/formulas/mathematics/college/l3wm82xwkqlvivdb694ivf5h5libfuj3wc.png)
Where a = 22 ft.
![A_{\text{equilateral}}=\frac{\sqrt[]{3}}{4}\cdot(22ft)^2=\frac{484\sqrt[]{3}}{4}ft^2=121\sqrt[]{3}ft^2](https://img.qammunity.org/2023/formulas/mathematics/college/wdssjuausnxuj2wx9i31806ripodgck79h.png)
Then, we find the area of the right triangle

At last, we add all three areas
![A=484ft^2+121\sqrt[]{3}ft^2+176ft^2\approx869.6ft^2](https://img.qammunity.org/2023/formulas/mathematics/college/u25wfc027u13y86xquwg8d4ut1lwooevyw.png)
Hence, the area of the composite figure is 869.6 square feet.