Part 1
Given the coordinates of ABC
A(3,-6), B(0,9), C(2,-1)
If you dilate the figure by a scale factor of 2. the coordinates of A' will be:

Part 2
Given the coordinates of ABC
A(4,-8), B(2,-4), C(0,4)
If you dilate the figure by a scale factor of 1/4. the coordinates of B' will be:

Part 3
Given the coordinates of ABC
A(3,-6), B(0,9), C(2,-1)
If you dilate the figure by a scale factor of 3. the coordinates of C' will be:

Part 4
Given the coordinates of ABC
A(6,0), B(-4,2), C(-8,-2)
If you dilate the figure by a scale factor of 2 1/2. the coordinates of B' will be:
