Question

Evaluate f(x) = e^3x+1 when x = 1. (Round to three decimal places.) Provide your answer below: f(1) =

Answer 1

Given the function :

`f(x)=e^(3x)+1`

We need to evaluate the function when x = 1

so,

`\begin{gathered} f(1)=e^(3\cdot1)+1=e^3+1=20.0855+1=21.086 \\ \\ f(1)=21.086 \end{gathered}`

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If the given function is :

`f(x)=e^(3x+1)`

so,

`f(1)=e^(3\cdot1+1)=e^(3+1)=e^4=54.598`