207k views
1 vote
Suppose the function f(x)=30(2)^x gives a beetle population after x weeks.How many beetles will there be after 56 days

User Minusf
by
6.7k points

1 Answer

3 votes

Answer:

7,680 beetles

Step-by-step explanation:

The function that gives the beetle population after x weeks is given below:


f\mleft(x\mright)=30\mleft(2\mright)^x

To determine the beetle population after 56 days, first convert 56 days to weeks.


56\text{ days=}(57)/(7)=8\text{ we}eks

Thus, the beetle population will be:


\begin{gathered} f(8)=30(2)^8 \\ =30*256 \\ =7,680 \end{gathered}

There will be 7,680 beetles after 56 days.

User Anna Vlasenko
by
6.8k points