I need help with a problem with solving by square roots in quadratic equation.

Question

asked Aug 24, 2023 218k views

1 Answer

Dhanushka · Answer 1 · 2023-08-30T20:08:59+0000

To solve for x, first, we add 3 to the given equation:

$\begin{gathered} 2(x+5)^2-3+3=44+3, \\ 2(x+5)^2=47. \end{gathered}$

Dividing by 2, we get:

Therefore:

$x+5=\pm\sqrt{(47)/(2)}.$

Finally, subtracting 5 we get:

$x=\pm\sqrt{(47)/(2)}-5.$

Answer:

$x=\operatorname{\pm}\sqrt{(47)/(2)}-5.$