Question

Find the equation of a line that contains the points (4,-1) and (-1,-4)

Answer 1

Let:

`\begin{gathered} (x1,y1)=(4,-1) \\ (x2,y2)=(-1,-4) \\ \text{The slope is given by:} \\ \text{Slope}=m=(y2-y1)/(x2-x1)=(-4-(-1))/(-1-4)=(-4+1)/(-5)=(-3)/(-5)=(3)/(5) \end{gathered}`

Using the slope point equation:

`\begin{gathered} y-y1=m(x-x1) \\ y-(-1)=(3)/(5)(x-4) \\ y+1=(3)/(5)x-(12)/(5) \\ y=(3)/(5)x-(12)/(5)-1 \\ y=(3)/(5)x-(17)/(5) \end{gathered}`