Answer
2.95 x 102₃
Procedure
1. The first step is to search for the formula of lithium carbonate or deduct it using nomenclature rules,
-The formula is Li₂CO₃
2. Then determine the molecular weight of the molecule
-The molecular weight is 73.891 g/mol
3. Convert from grams to moles and from moles to molecules
![36.2\text{ g Li}_2\text{CO}_3\frac{1\text{ mol}}{73.891\text{ g}}\frac{6.022*10^(23)}{1\text{ mole}}=2.95*10^{23\text{ }}molecules](https://img.qammunity.org/2023/formulas/chemistry/college/hu203d1wr8dcqyc5gnliwbcgb5hf66l49k.png)