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The vertex of this parabola is at (-2, 1). Which of the following could be itsequation?5(-2,1)A. x = 4(y- 1)2-2B. y = 4(x - 2)2 + 1c. y = 4(x - 2)2-1D. x = 4(y + 1)2-2

The vertex of this parabola is at (-2, 1). Which of the following could be itsequation-example-1
User Tadas T
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1 Answer

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A parabola can be written in the vertex form as follows:


y=a(x-h)^2+k

Where:


(h,k)

Are the coordinates of the vertex.

Since the vertex is at:


\begin{gathered} (h,k)=(-2,1) \\ \end{gathered}

The equation is:


\begin{gathered} y=a(x-(-2))^2+1 \\ y=a(x+2)+1 \end{gathered}

But, since it is a horizontal parabola:


\begin{gathered} x=a(y-k)+h \\ so\colon \\ x=a(y-1)^2-2 \end{gathered}

Therefore, the only valid option is:


x=4(y-1)^2-2

User Praween K
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