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If m<1=(4x + 7), m<2= (15x - 17), and m<3= (6x -13), thenfind the value of x.

If m<1=(4x + 7), m<2= (15x - 17), and m<3= (6x -13), thenfind the value of-example-1
User D Hudson
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1 Answer

4 votes

In this problem we have that

m<1+m<2=180 ------> by form a linear pair

and

m<1=m<3 -----> by vertical angles

method 1

m<1+m<2=180

substitute the given values

(4x+7)+(15x-17)=180

solve for x

19x=180+10

19x=190

x=10

method 2

m<1=m<3

substitute the given values

4x+7=6x-13

solve for x

6x-4x=7+13

2x=20

x=10

User Maurits De Boer
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4.7k points