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Hello! In thought I knew how to solve this but none of my answers are options

Hello! In thought I knew how to solve this but none of my answers are options-example-1

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The surface area (S) of a rectangular pyramid is:


S=A+(1)/(2)(p*s)

Where:

A = area of base

p = perimeter of base

s = slant height

First, let's find the area of the base:


\begin{gathered} A=12.2*12.2 \\ A=148.84ft^2 \end{gathered}

Second, let's find the perimeter of the base:


\begin{gathered} p=12.2+12.2+12.2+12.2 \\ p=48.8ft \end{gathered}

The slant is given and is 9.5 ft.

So, let's substitute the values and find the surface area:


\begin{gathered} S=148.84+(1)/(2)(48.8*9.5) \\ S=148.84+231.8 \\ S=380.64ft^2 \end{gathered}

Answer: The surface area is 380.64 ft².

User Jeton
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