1 Answer

Anuith · Answer 1 · 2023-08-22T16:21:43+0000

Answer:

0.124moles

According to the ideal gas equation

PV = nRT

Given the following parameters

Volume V = 347mL = 0.347L

Pressure P = 6680torr = 8.79atm

R = 0.08205Latm/molK

Temperature T = 27 + 273 = 300K

Substitute the given parameters into the formula

$\begin{gathered} n=(PV)/(RT) \\ n=(8.79*0.347)/(0.08205*300) \\ n=(3.05)/(24.615) \\ n=0.124moles \end{gathered}$

Hence the required moles of nitrogen is 0.124moles