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What is the area of a rectangle with vertices at (-3, -1),(1, 3),(3, 1) and (-1, -3)?

What is the area of a rectangle with vertices at (-3, -1),(1, 3),(3, 1) and (-1, -3)?-example-1
User Molochdaa
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1 Answer

1 vote

The rectangle is given by:

The area of this rectangle is given by:


\begin{gathered} A=w\cdot h \\ \end{gathered}

Where:


\begin{gathered} w=\sqrt[]{(3-(-1))^2+(1-(-3))^2} \\ w=4\sqrt[]{2} \end{gathered}
\begin{gathered} h=\sqrt[]{(-1-(-3))^2+(-3-(-1))^2} \\ h=2\sqrt[]{2} \end{gathered}

Therefore:


\begin{gathered} A=4\sqrt[]{2}\cdot2\sqrt[]{2} \\ A=16 \end{gathered}

Answer:

16 units²

What is the area of a rectangle with vertices at (-3, -1),(1, 3),(3, 1) and (-1, -3)?-example-1
User Dushyant Gill
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