Question

Consider the linear equation:2y + 3 = 0Step 1 of 2: Find two points on the line to be graphed.

Answer 1

Given the linear equation

`2y+3=0`

To begin with, let us make y the subject of the question

`\begin{gathered} 2y=0-3 \\ 2y=-3 \\ \\ y=-(3)/(2) \end{gathered}`

The graph of the function is given below

The points on the graph include

`(0,-1.5)\text{ and (3,-1.5)}`

For fraction we will have

`(0,-(3)/(2))\text{ and (}3,-(3)/(2)\text{)}`