ANSWER
B. 1.78 x 10⁷ J
Step-by-step explanation
Given:
• The power of the washer, P₁ = 450 W
,
• The power of the dryer, P₂ = 3000 W
,
• The time needed to wash one load of clothes, t₁ = 1 hour
,
• The time needed to dry those clothes, t₂ = 1.5 hours
Energy is the product of power and time,
![E=P\cdot t](https://img.qammunity.org/2023/formulas/physics/college/gs9czk2znllzr5kgl58umcnesosi03dk7k.png)
If the power is given in watts, we have to convert the time to seconds, so that the energy is in Joules. Knowing that 1 hour has 3600 seconds,
![\begin{gathered} t_1=1hour\cdot(3600s)/(1hour)=3600s \\ \\ t_2=1.5hour\cdot(3600s)/(1hour)=5400s \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/47sdlq7ricmczy48ysrfs78mz6v9nlkeo2.png)
So the energy needed to wash the clothes is,
![E_1=P_1\cdot t_1=450W\cdot3600s=1.62\cdot10^6J](https://img.qammunity.org/2023/formulas/physics/college/nggkjx1mpqg434aet7ankkffuxc79uks8a.png)
And the energy needed to dry them,
![E_2=P_2\cdot t_2=3000W\cdot5400s=16.2\cdot10^6J](https://img.qammunity.org/2023/formulas/physics/college/yk70mhuwu0wowfvm0ddypvk5u2rd9b9htx.png)
So, the total energy needed for the whole cycle is,
![E=E_1+E_2=1.62\cdot10^6J+16.2\cdot10^6J=(1.62+16.2)\cdot10^6J=17.82\cdot10^6J=1.78\cdot10^7J](https://img.qammunity.org/2023/formulas/physics/college/ku0cfhrbko46qq6c3me47k0ltbct5ynxjp.png)
Hence, the energy needed to wash the clothes for 1 hour and dry them for 1.5 hours is 1.78 x 10⁷ J.