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oWhich is the general form of the equation of the circleshown?O x2 + y2 + 4x – 2y -4 = 0O x2 + y2 + 4x – 2y + 2 = 0O x2 + y2 4x + 2y - 4 = 0O x2 + y2 4x + 2y + 2 = 0Save and ExitNextSubmitlandet

User Reuven Lax
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1 Answer

4 votes

Answer

Option A is correct.

The equation of the circle shown in general form is

x² + y² + 4x - 2y - 4 = 0

Step-by-step explanation

The equation of a circle with center (h, k) and radius r is given as

(x - h)² + (y - k)² = r²

For this question,

Center = (h, k) = (-2, 1)

h = -2, k = 1

Radius = 3 units (Distance from the center of the circle to any point on the circumference of the circle)

(x - h)² + (y - k)² = r²

(x - (-2))² + (y - 1)² = 3²

(x + 2)² + (y - 1)² = 9

x² + 4x + 4 + y² - 2y + 1 = 9

x² + y² + 4x - 2y + 4 + 1 - 9 = 0

x² + y² + 4x - 2y - 4 = 0

Hope this Helps!!!

User Gal Margalit
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