Part A.
Let x be the number of months. Since the rate is $44 per month and the initial fee is $48, the linear model is:
![C(x)=44x+48](https://img.qammunity.org/2023/formulas/mathematics/college/um25kz8w0lg63a1il577v5q50e7mghw20o.png)
where C(x) denotes the total cost.
Part B.
In this case, we must substitute x=6 into our linear model. It yields,
![C(6)=44(6)+48](https://img.qammunity.org/2023/formulas/mathematics/college/ebemb6v8ul5svey8sqi3vqb7k45dgtmxan.png)
which gives
![\begin{gathered} C(6)=264+48 \\ C(6)=312 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/j6nm9c0qb8zb62wbtnku20aiqypz4ntzxz.png)
Therefore, after 6 months, the total cost will be $312.
Part C.
In this case, the second company has a rate of $62 per month with no initial fee. Then, the linear model for the second company is
![\begin{gathered} B(x)=62x+0 \\ or\text{ equivalently, } \\ B(x)=62x \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/6mqltthl5dbwtxjqwlmfta27k49x7n7wdc.png)
where now B(x) denotes the total cost for the second company.
Then, since you have $620, we can compare both companies by substituting the total cost of $620 into the two linear models, that is,
![\begin{gathered} 620=44x+48 \\ \text{and} \\ 620=62x \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/rtkrtqvcq1a7hx5vcv6of27i8a09bi81ll.png)
and finc x for each model.
Then, the first model yields,
![\begin{gathered} 44x=620-48 \\ 44x=572 \\ x=(572)/(44) \\ x=13\text{ months} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/eiupgiuuny2nzw9ucdj3b9vk97lhqcfb36.png)
and the second equation gives
![\begin{gathered} x=(620)/(62) \\ x=10\text{ months} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/s5m3j6iut0ca6daare08kymkhe3cd56wn1.png)
By comparing both result, we can see that the best choice in the first company with 13 months