46.8k views
0 votes
If 49x^2 - b = (7x+1/2)(7x-1/2), then find the value of b.

User Xephryous
by
8.1k points

1 Answer

3 votes

Given:


49x^2-b=(7x+(1)/(2))(7x-(1)/(2))

To find the value of b:

Using the identity,


(a+b)(a-b)=a^2-b^2

So, the given expression can be written as,


\begin{gathered} 49x^2-b=(7x)^2-((1)/(2))^2 \\ 49x^2-b=49x^2-(1)/(4) \\ -b=49x^2-(1)/(4)-49x^2 \\ -b=-(1)/(4) \\ b=(1)/(4) \end{gathered}

Hence, the value of b is,


(1)/(4)

User Sham Dhiman
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories