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A group of people were asked which of three ice cream flavors they prefer. The results are shown in the table.AgesVanillaStrawberryChocolate20 years and younger8106Over 20 years8612What is the probability of a person being 20 years or younger and preferring strawberry ice cream?

A group of people were asked which of three ice cream flavors they prefer. The results-example-1

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We have a two-way frequency table here, and to find the probability, we need to find the total of people surveyed to find the asked probability.

1. Then we have to add the rows, and also the columns to obtain the following table:

2. Now, we can see that the total of asked people is 50.

3. Now to find the probability of a person being 20 years and younger AND preferring strawberry ice cream, we can see that we need to find the intersection of the probability of both events, and this is as follows:


\begin{gathered} \text{ Event 20 years and younger=A} \\ \\ \text{ Event Preferring strawberry ice cream=B} \\ \\ P(A\cap B)=(10)/(50)=(1)/(5)=0.2=20\% \\ \\ P(A\cap B)=20\% \end{gathered}

Therefore, the probability of a person being 20 years and younger AND preferring strawberry ice cream is 20% (last option).

A group of people were asked which of three ice cream flavors they prefer. The results-example-1
User Paul Harrington
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