Question

Which of the following values of x satisfy the equation 3x2 - 8x + 4 = 0?DA2x = 2 and x =3WNoB1x = 4 and x =312x = -2 and x =WN3D1x = -4 and x =3

Answer 1

To solve this, we need to use the quadratic formula.

When we have an equation of the form:

`ax^2+bx+c=0`

We can use:

`x_(1,2)=\frac{-b\pm\sqrt[]{b^2-4\cdot a\cdot c}}{2\cdot a}`

In this case, we have the equation:

`3x^2-8x+4=0`

With:

a = 3

b = -8

c = 4

Then:

`x_(1,2)=\frac{-(-8)\pm\sqrt[]{(-8)^2-4\cdot3\cdot4}}{2\cdot3}`

THen solve:

`\begin{gathered} x_(1,2)=\frac{8\pm\sqrt[]{64^{}-48}}{6} \\ x_(1,2)=\frac{8\pm\sqrt[]{16}}{6} \\ x_(1,2)=(8\pm4)/(6) \end{gathered}`

THen the two solutions are:

`\begin{gathered} x_1=(8+4)/(6)=(12)/(6)=2 \\ x_2=(8-4)/(6)=(4)/(6)=(2)/(3) \end{gathered}`

Thus, the correct answer is option A