Question

The highest point along a cliff is 80 m above the lakeshore. A surveyor stands on thetop of the cliff, looking through a 1.5 m tall transit instrument. He spots a boat outon the lake, at an angle of depression of 38°. How far, to the nearest tenth of ametre, is it from the boat to the base of the cliff? Show your work.

Answer 1

`\begin{gathered} TOA \\ \tan38^0=(opp)/(adj) \\ tan38^0=(81.5)/(x) \\ \\ x=(81.5)/(tan38) \\ \\ x=104.3meters \end{gathered}`

The distance from the base of the cliff to the boat is 104.3 meters