174k views
3 votes
How many real solutions does the graph of \displaystyle y=-2x^2+8x-8y=−2x 2 +8x−8have?

1 Answer

4 votes

we have

y=-2x^2+8x-8

Looking at the graph

the number of real solutions in a quadratic equation is equal to the number of x-intercept

In this problem

the graph has only one x-intercept (2,0)

therefore

has only one real solution

User Sunflame
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories