a) The coordinates of P and Q are P(0, 4) and Q(-3, 0).
b) The points P and Q are shown on the graph in the picture below.
c) A graph of the line 3y - 4x = 12 for values of x from -3 to 3 is shown below.
In order to complete the coordinates of P and Q, we would substitute the given x-coordinate and y-coordinate into the equation of the line and then evaluate as follows;
3y - 4x = 12
3y - 4(0) = 12
3y = 12
y = 12/3
y = 4
P (x, y) = P (0, 4), which is the y-intercept.
3(0) - 4x = 12
4x = -12
x = -12/4
x = -3
Q (x, y) = Q (-3, 0), which is the x-intercept.
Part b.
In this exercise, we would use an online graphing tool to plot the points P and Q as shown on the graph in the picture below.
Part c
A graph of the line 3y - 4x = 12 for values of x from -3 to 3 is shown below.
Complete Question:
P and Q are points on the line 3y-4x=12
a) Complete the coordinates of P and Q. P(0, _) Q(_,0)
b) Plot points P and Q on the graph. Use the x+ tool to plot the coordinates.
c) Draw the line 3y - 4x = 12 for values of x from -3 to 3.