Question

Please help me with this quickly, the questions says to show work or explain but I want the work, thank you!

Answer 1

`\begin{gathered} P(Orange)=(1)/(10) \\ P(Green)=(1)/(5) \\ P(Blue)=(1)/(6) \end{gathered}`

Step-by-step explanation

Given:

A table of experimental data

Desired Outcome:

Experimental probability of spinning orange, green and blue.

Probability of an Event A:

`P(A)=\frac{number\text{ of outcomes in A}}{Total\text{ number of outcomes in Sample Space}}`

Experimental probability of spinning orange:

`\begin{gathered} P(orange)=(3)/(7+3+1+6+5+8) \\ P(orange)=(3)/(30) \\ P(orange)=(1)/(10) \end{gathered}`

Experimental probability of spinning green:

`\begin{gathered} P(green)=(6)/(30) \\ P(green)=(1)/(5) \end{gathered}`

Experimental probability of spinning blue:

`\begin{gathered} P(blue)=(5)/(30) \\ P(blue)=(1)/(6) \end{gathered}`

Hence, the experimental probability of spinning orange, green and blue are 1/10, 1/5 and 1/6 respectively.