The given equation is
- 3 + √(3x - 11) = 5
Adding 3 to both sides of the equation, we have
- 3 + 3 + √(3x - 11) = 5 + 3
√(3x - 11) = 8
Square both sides. It becomes
[√(3x - 11)]^2 = 8^2
3x - 11 = 64
Adding 11 to both sides of the equation, we have
3x - 11 + 11 = 64 + 11
3x = 75
Dividing both sides by 3,
3x/3 = 75/3
x = 25