Question

(sorry the picture is sideways, i couldn’t type in the problem directly hopefully this will do)

Answer 1

The angle can be expressed as,

`\begin{gathered} (13\pi)/(6)=(2\pi+(\pi)/(6)_{}) \\ \end{gathered}`

So, the angle can be drawn as,

To find the reference angle if the angles is greeter than 2π, we first subtract 2π from the angle(here 13π/6) until it is below 2π.

`(13\pi)/(6)-2\pi=(\pi)/(6)`

So, the reference angle is π/6.