Question

Question 60/1 pt 101 DetailsIf it takes 0.621 L of 0.7 M NaOH to neutralize 9.3 L of an HCLsolution, what is the concentration of HCL?

Answer 1

The concentration of HCl is 0.0467 M.

Step-by-step explanation:

What is given?

Volume 1 (V1) = 0.621 L,

Concentration 1 (C1) = 0.7 M,

Volume 2 (V2) = 9.3 L.

What do we need? Concentration 2 (C2).

Step-by-step solution:

To solve this problem we have to use the following formula:

`C_1V_1=C_2V_2.`

Where in this case, concentration and volume 1 correspond to NaOH, and concentration and volume 2 correspond to HCl.

We want to find the concentration of HCl so we have to solve for 'C2' and replace the given data in the formula, like this:

`\begin{gathered} C_2=(C_1V_1)/(V_2), \\ \\ C_2=\frac{0.7\text{ M}\cdot0.621\text{ L}}{9.3\text{ L}}, \\ \\ C_2=0.0467\text{ M.} \end{gathered}`

The answer would be that the concentration of HCl is 0.0467 M.