The image is real because the light rays actually converge at the image point. The image is inverted because the three light rays intersect below the principal axis. The image is magnified because the image distance is greater than the object distance.
Therefore, the answer is D. The image is upside down.
The image formed is real, inverted, and magnified.
To see this, let's consider the three light rays traced in the diagram:
* Ray 1: This ray travels parallel to the principal axis of the mirror and is reflected through the focal point.
* Ray 2: This ray passes through the focal point and is reflected parallel to the principal axis.
* Ray 3: This ray passes through the center of curvature, C, and is reflected back on itself.
These three rays intersect at a point beyond the center of curvature, C. This point is the location of the image.
The image is real because the light rays actually converge at the image point. The image is inverted because the three light rays intersect below the principal axis. The image is magnified because the image distance is greater than the object distance.
Therefore, the answer is D. The image is upside down.
Note that the other options are incorrect:
* A. No image is formed: An image is always formed when an object is placed in front of a concave mirror.
* B. The image is reduced: The image is magnified when the object is placed between the center of curvature and the focal point of a concave mirror.
* C. The image is virtual: A virtual image is formed when the light rays do not actually converge at the image point. The image formed in this case is real.