Question

How many moles of Pb(NO3)2 are requiredif 12 moles of AI(NO3)3 are produced?3Pb(NO3)2 + 2AlCl3 → 3PbCl2 + 2AI(NO3)3

Answer 1

Answer: 18 moles

Step-by-step explanation:

Answer 2

18 moles Pb(NO₃)₂

Explanation

Given:

Moles of AI(NO₃)₃ produced = 12 moles

Equation: 3Pb(NO₃)₂ + 2AlCl₃ → 3PbCl₂ + 2AI(NO₃)₃

What to find:

The moles of Pb(NO₃)₂ required to produce 12 moles of AI(NO₃)₃.

Solution:

Let the moles of Pb(NO₃)₂ required be represented as x.

From the given equation;

3 moles Pb(NO₃)₂ produced 2 moles AI(NO₃)₃

x moles Pb(NO₃)₂ will produce 12 moles AI(NO₃)₃

Cross multiply and divide both sides by 2 moles AI(NO₃)₃

`x=\frac{12\text{ }moles\text{ }Al\left(NO₃\right)₃}{2\text{ }moles\text{ }Al\left(NO₃\right)₃}*3\text{ }moles\text{ }Pb(NO_3)_2=18\text{ }moles\text{ }Pb(NO_3)_2`

Therefore, 18 moles of Pb(NO₃)₂ are required to produce 12 moles of AI(NO₃)₃.