The Solution:
Given that p and q are inversely related, we have that:

This means that:

Given the initial condition (or values) that p =30 when q = 25.
Substituting these values in the relation above, we get

Cross multiplying, we get

So, the formula connecting p and q is obtained as

We are asked to find the value of q when p = 50.
Substitute 50 for p in the formula connecting p and q.

Cross multiplying, we get

Dividing both sides by 50, we get

Therefore,