Question

I'm put at a dilemma on my project need help

Answer 1

see the figure below with letters to better understand the problem

step 1

Find out the length BC in the right triangle BDC

we have a 45-90-45 degrees triangle

`\begin{gathered} cos(45^o)=(BC)/(DC)=(BC)/(6) \\ cos(45^o)=(√(2))/(2) \end{gathered}`

Find out the value of BC

`\begin{gathered} (BC)/(6)=(√(2))/(2) \\ BC=3√(2) \end{gathered}`

step 2

In the right triangle ABC

`\begin{gathered} sin30^o=(BC)/(AC) \\ \\ AC=(BC)/(sin30^o) \end{gathered}`

we have

`\begin{gathered} BC=3√(2) \\ sin30^o=(1)/(2) \end{gathered}`

substitute

`\begin{gathered} AC=(3√(2))/((1)/(2))=6√(2) \\ AC=8.5\text{ m} \end{gathered}`

The answer Part A is 8.5 meters

Part B

Find out the difference

8.5-6=2.5 meters

The answer Part B is 2.5 meters