Solution
Explanation:
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
![E(x)\text{ = np}](https://img.qammunity.org/2023/formulas/mathematics/college/3uk3e3qvdpzkbkybuxigg2jhc9515ti3co.png)
The standard deviation of the binomial distribution is:
![\sigma\text{ = }√(np(1-p))](https://img.qammunity.org/2023/formulas/mathematics/college/erj5js866r0v8tmyegwq8fthlv4s4gcwbq.png)
Normal probability distribution
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
![z\text{ = }(x-\mu)/(\sigma)](https://img.qammunity.org/2023/formulas/mathematics/college/szgqo1h52xjk9m3u8gun8dj84dur4zbadj.png)
p = 61% = 0.61
n = 149
![\begin{gathered} \mu\text{ = np = 149 }*0.61\text{ = 90.89} \\ \\ \sigma\text{ = }√(np(1-p))\text{ = }√(90.89*0.39)\text{ = 5.95} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/89gqrgx64hxfgzw76vr3ppxkp05j4qmyzy.png)
![\begin{gathered} z\text{ = }(x-\mu)/(\sigma)\text{ = }(94-90.89)/(5.95) \\ \\ z\text{ = 0.523} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/qshb506kq7tfrc7rqu0wptg9e0048nikzm.png)