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If h(x) = 6 - x, what is the value of (h°h)(10)?A. -4B. -2C. 10D. 16

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h(x ) = (6 - x)


(h^oh)(x)=h\lbrack h(x)\rbrack

= 6 - (6 - x)

= 6 - 6 + x

= x

To get (h°h)(10), simply substitute x= 10

(h°h)(10) = 10

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