We are given that
In right triangle ABC, if angle A is 90 degrees, angle C is 34 degrees, and AC is 71.4, find BC.
Solution
We will first draw a diagram to illustrate the information
Above we want to find x
The method to use is SOHCAH
From the right angle triangle above we have above, we have the adjacent side and we want to find the hypotenus, so we use cosine
i.e
![\cos 34=(71.4)/(x)](https://img.qammunity.org/2023/formulas/mathematics/high-school/1st510khvx9g7lvhjw0or7kq0f0ypu9ww3.png)
We need to solve for x here
![\begin{gathered} x=(71.4)/(\cos 34) \\ x=86.12396152 \\ x=86.1\text{ (to the nearest tenth)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/usm4wyufi4111pc3b2eqbwi0spmy2irjog.png)
Thus, |BC| = 86.1 (to the nearest tenth