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Consider a normal distribution with mean 35 and standard deviation 4. What is the probability a value selected at random from this distribution is greater than 35? (Round your answer to two decimal places.)

User Shishram
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Given the Mean:


\mu=35

And the Standard Deviation:


\sigma=4

You need to find:


P(X>35)

You can find the z-statistics using this formula:


z=(X-\mu)/(\sigma)

In this case, you need to set up that:


X=35

Then, substituting values and evaluating, you get:


z=(35-35)/(4)=0

Therefore, you need to find:


P(z>0)

Using the Normal Distribution Table for that z-statistic, you get:


P(z>0)=0.50

Hence, the answer is:


P(X>35)=0.50

User BobbyMick
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