Question

What is the critical angle for the boundary between an unknown medium (n=2.07) and water (n=1.33)?

Answer 1

`\begin{equation*} 40.0\degree \end{equation*}`

Step-by-step explanation

To find the critical angle for the boundary, we have to apply the formula:

`\theta=\sin^(-1)((n_r)/(n_i))`

where nr = refraction index = 1.33

ni = incident index = 2.07

Hence, the critical angle for the boundary is:

`\begin{gathered} \theta=\sin^(-1)((1.33)/(2.07)) \\ \theta=\sin^(-1)(0.6425) \\ \theta=40.0\degree \end{gathered}`

That is the answer.