Let x represent the number of the days the saw is rented and y represents the charge to the user in dollar
There is a $40 fee (constant) to rent a chain saw plus $9 per day (9x)
a) m is the charge per day
b is the constant
![y=9x+40](https://img.qammunity.org/2023/formulas/mathematics/college/qgaxe6qtw8b0snkjsrhawd2ia3rx6yz20p.png)
b) Find y when x=5
![\begin{gathered} y=9(5)+40 \\ y=45+40 \\ y=85 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/tmee0nax7n25xsf4suv2i0n1yvjrzx9dh0.png)
For 5 days of rent the saw the charge is $85
Ordered pair (5,85)
c) if the total charge is $184, for how many days is the saw rented?
Solve x when y=184
![\begin{gathered} 184=9x+40 \\ 184-40=9x \\ 144=9x \\ x=(144)/(9) \\ \\ \\ x=16 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/8qq0m95opk19mof2jdlww0t4t7vhmt5j3e.png)
The saw was rented for 16 days
Then, the equation for the situation is y=9x+40; the ordered pair for x=5 is (5,85) and it means that for 5 days of rent the saw the charge is $85; and if the total charge is $184 the saw was rented for 16 days