Given that the mass of the block is m = 17.7 kg
The force exerted on it is F = 175 N.
The angle is
![\theta=35.8^(\circ)](https://img.qammunity.org/2023/formulas/physics/college/bnnbbo8pqzsw8jdp1m84f2czk16pr4xmax.png)
We have to find the normal force.
The normal force can be calculated by the formula,
![N=mg-F\sin \theta](https://img.qammunity.org/2023/formulas/physics/college/efkdpk0j1i3o4m3rcdijxt5cigxn9dse6s.png)
Here, g = 9.81 m/s^2 is the acceleration due to gravity.
Substituting the values, the normal force will be
![\begin{gathered} N=17.7*9.81-175sin35.8^(\circ) \\ =173.64-102.36 \\ =71.28\text{ N} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/1lch6na7nfb9s1vq6lnf8480hihsar3yao.png)
Thus, the normal force is 71.28 N