Solution:
Given:
Integers from 1 to 100.
Integers are whole numbers that can be positive, negative or zero.
Hence, integers between 1 to 100 are positive whole numbers between 1 and 100.
This is an example of arithmetic sequence increasing by a common difference of 1.
Using the formula for the sum of an arithmetic sequence,
![\begin{gathered} S_n=(n)/(2)(2a+(n-1)d) \\ \text{where;} \\ n\text{ is the number of terms, n = 100} \\ a\text{ is the first term, a = 1} \\ d\text{ is the co}mmon\text{ difference, d = 1} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ysqohgekrx8cpxeyqtr80x2baodutlcmdh.png)
Hence,
![\begin{gathered} S_n=(n)/(2)(2a+(n-1)d) \\ S_(100)=(100)/(2)(2(1)+(100-1))1 \\ S_(100)=50(2+99) \\ S_(100)=50(101) \\ S_(100)=50*101 \\ S_(100)=5050 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gm6w4h6t1frmkua2mdi1vrbbfr1th9nzrt.png)
Alternatively using another formula,
![\begin{gathered} S_n=(n)/(2)(a+l) \\ \text{where;} \\ a\text{ is the first term, a = 1} \\ n\text{ is the number of terms, n = 100} \\ l\text{ is the last term, l = 100} \\ \\ S_n=(n)/(2)(a+l) \\ S_(100)=(100)/(2)(1+100) \\ S_(100)=50(101) \\ S_(100)=50*101 \\ S_(100)=5050 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/r7w0bjlu9ozmq8xvlfb574s0e03i2sb02w.png)
Therefore, the sum of the integers from 1 to 100 is 5050.