Question

if a 0.040-kg stone is whirled horizontally on the end of a 60-m string at a speed of 4.4 m/s, what is the centripetal force ? * 0.013 n 4 n 0. 32 n 20.1 n

Answer 1

0.013N

Step-by-step explanation:

`F=(mv^(2) )/(r)`

m=0.04, v=4.4m/s, r=60

F=0.013 N