Question

How do I find the x-intercept and y-intercept of 2x+2y=2

Answer 1

Given the function:

`2x+2y=2`

x-intercept is when y = 0, so we substitute y=0 into the equation and solve for x:

`\begin{gathered} 2x+2(0)=2 \\ 2x+0=2 \\ 2x=2 \\ (2x)/(2)=(2)/(2) \\ x=1 \end{gathered}`

So, x-intercept = (1,0)

y-intercept is when x = 0:

`\begin{gathered} 2(0)+2y=2 \\ 0+2y=2 \\ 2y=2 \\ (2y)/(2)=(2)/(2) \\ y=1 \end{gathered}`

So, y-intercept = (0,1)

Answer:

x-intercept = (1,0)

y-intercept = (0,1)