Answer:
![227.8\text{ mL}](https://img.qammunity.org/2023/formulas/chemistry/college/sp0716vp7udmcxlwbek8trd3vjw6c7sspd.png)
Step-by-step explanation:
Here, we want to get the volume of the gas at the new temperature
According to Charles' law, the volume of a given mass of gas is directly proportional to the temperature in Kelvin
Mathematically:
![(V_1)/(T_1)\text{ = }(V_2)/(T_2)](https://img.qammunity.org/2023/formulas/chemistry/college/mq1b98et5qttc2b64p1vt4fuv4c8aybqvr.png)
where:
V1 is the initial volume which is 220 mL
T1 is the initial temperature (we convert this to Kelvin by adding 273 : 10 + 273 = 283 K)
V2 is the final volume which is what we want to calculate
T2 is the final temperature which is (20 + 273 = 293 K)
Substituting the values:
![V_2\text{ = }(220*293)/(283)\text{ = 227.8 mL}](https://img.qammunity.org/2023/formulas/chemistry/college/rdhbar38vvoxtpyc9ktqg70776n6rgmtgx.png)