Question

I need help with Part c).angle of elevation. 29 degrees angle of depression. 18 degrees

Answer 1

From the diagram, we get that the height we are looking for is h₂*0.914. To compute h₂ we notice that it is equal to the tangent of the depression angle times 31 yds.

Therefore:

`\begin{gathered} h_2=\tan (18^(\circ))*31\text{yds,} \\ h_2\approx10.0725\text{ yds.} \end{gathered}`

Answer: 9.21 meters.