Given that polygon ABCD is congruent to PQRS, then angle B is congruent to angle Q.
Let's call angle B' to the suplement of angle B. Then,
∠B + ∠B' = 180°
65° + ∠B' = 180°
∠B' = 180° - 65°
∠B' = 115°
If ∠B ≅ ∠Q, then ∠B' ≅ ∠Q' (where ∠Q' is the suplement of angle Q). So,
∠Q = 65°
∠Q' = 115°
A. True
B. False
C. True