Question

For the reaction between Zn and HCI write out the two redox half reactions

Answer 1

Zn(s) + 2HCL(aq) → ZnCl2(aq) + H2 (g)

Oxidation half reaction will be :

1. H2 → HCL

H2 → h^2+ ( electron release oxidation process)

2. H2 ^0 →H^+1 + 1e ( electron release oxidation process) take note that one electron is required for balancing both sides.

(Extra notes for reduction process that also takes place : ZnCl2 → Zn

Zn^2+ → Zn ^0 (electron accept reduction process)