Question

Ab=BC how do I calculate the size of Angle abc?

Answer 1

Step 1:

In this question, we are meant to find the size of angle ABC, using the diagram below:

From the diagram,

we can see that the base angles are equal, which makes it have the property of the Isosceles Triangle.

Step 2:

Since the base angles are equal, then

`\begin{gathered} \angle A=40^0 \\ \angle C=40^0 \end{gathered}`

Now, to get angle B, we need to show that:

`\begin{gathered} \angle\text{ A + }\angle B\text{ +}\angle C=180^0 \\ 40^0_{}+\angle B+40^0=180^0 \\ \angle B+80^0=180^0 \\ \angle B=180^0-80^0 \\ \angle B=100^0 \end{gathered}`

CONCLUSION:

`\begin{gathered} \angle A=40^0 \\ \angle B=100^0 \\ \angle C=40^0 \end{gathered}`