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I'm having a very hard time with this I would love some help on how to do it

I'm having a very hard time with this I would love some help on how to do it-example-1

1 Answer

4 votes

Answer

a) Margin of Error = 0.684

Lower limit = 13.62

Upper limit = 14.98

b) If the population is not normally distributed, the conditions that need to be satisfied include

- large enough sample size n.

- population standard deviation must be known or provided.

- simple random sample must be used.

c) Yes, the result in (a) is valid as it satisfies every required condition required to calculate the confidence interval.

Step-by-step explanation

a) Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Sample mean = 14.3

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value at 93% confidence interval for sample size is obtained from the z-tables because the population standard deviation is known (2).

Critical value = 1.81

Standard error of the mean = σₓ = (σ/√n)

σ = standard deviation of the sample = 2

n = sample size = 28

σₓ = (2/√28) = 0.378

Confidence Interval = (Sample mean) ± (Margin of error)

93% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error)]

CI = 14.3 ± (1.81 × 0.378)

CI = 14.3 ± 0.684

93% CI = (13.62, 14.98)

b) If the population is not normally distributed, the conditions that need to be satisfied include

- large enough sample size n.

- population standard deviation must be known or provided.

- simple random sample must be used.

c) Yes, the result in (a) is valid as it satisfies every required condition required to calculate the confidence interval.

Hope this Helps!!!

User Moe Steen
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