Question

Read image for instructions Fill in the blanks for the equation

Answer 1

`\begin{gathered} \text{ The equation of the circle is given by} \\ (x-h)^2+(y-k)^2=r^2 \\ \text{where} \\ (h,k)\text{ is the coordinate of the center of the circle, and} \\ r\text{ is the radius} \\ \text{A circle with a center of }(-4,2)\text{ and radius }1\text{ would therefore have an equation of} \\ (x-(-4))^2+(y-2)^2=1^2 \\ \Rightarrow(x+4)^2+(y-2)^2=1^2 \\ \Rightarrow(x+4)^2+(y-2)^2=1^{} \end{gathered}`